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-22x^2+484x=0
a = -22; b = 484; c = 0;
Δ = b2-4ac
Δ = 4842-4·(-22)·0
Δ = 234256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{234256}=484$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(484)-484}{2*-22}=\frac{-968}{-44} =+22 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(484)+484}{2*-22}=\frac{0}{-44} =0 $
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